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4y^2-15y-8=0
a = 4; b = -15; c = -8;
Δ = b2-4ac
Δ = -152-4·4·(-8)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{353}}{2*4}=\frac{15-\sqrt{353}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{353}}{2*4}=\frac{15+\sqrt{353}}{8} $
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